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Macroeconomics 4

More on Bellman equation

v(x)=max⁑yβˆˆΞ“(x){F(x,y)+Ξ²v(y)}v(x)=\max _{y \in \Gamma(x)}\{F(x, y)+\beta v(y)\}

we define the following operator T:

(Tv)(x)=max⁑yβˆˆΞ“(x){F(x,y)+Ξ²v(y)}(T v)(x)=\max _{y \in \Gamma(x)}\{F(x, y)+\beta v(y)\}

A solution to the functional equation is then a fixed point of this operator

vβˆ—=Tvβˆ—v^{*}=T v^{*}
  • Complete Metric Spaces (domain and range of the operator T)
  • Contraction Mapping Theorem (existence and uniqueness of the operator T)
  • Blackwell's theorem (sufficient condition for an operator to be a contraction)

CMT#

Definition 33 Let (S,d)(S, d) be a metric space and T:Sβ†’ST: S \rightarrow S be a function mapping SS into itself. The function TT is a contraction mapping if there exists a number β∈(0,1)\beta \in(0,1) satisfying

d(Tx,Ty)≀βd(x,y)Β forΒ allΒ x,y∈Sd(T x, T y) \leq \beta d(x, y) \text { for all } x, y \in S

The number Ξ²\beta is called the modulus of the contraction mapping.

Theorem 35 ==CMT== Let (S,d)(S, d) be a complete metric space and suppose that T:Sβ†’ST: S \rightarrow S is a contraction mapping with modulus Ξ²\beta. Then a) the operator TT has exactly one fixed point vβˆ—βˆˆSv^{*} \in S and b) for any v0∈Sv_{0} \in S, and any n∈Nn \in \mathbf{N} we have

d(Tnv0,vβˆ—)≀βnd(v0,vβˆ—)d\left(T^{n} v_{0}, v^{*}\right) \leq \beta^{n} d\left(v_{0}, v^{*}\right)

Blackwell's Theorem#

Theorem 37 Let XβŠ†RLX \subseteq \mathbf{R}^{L} and B(X)B(X) be the space of bounded functions ff : Xβ†’RX \rightarrow \mathbf{R} with the dd being the sup-norm. Let T:B(X)β†’B(X)T: B(X) \rightarrow B(X) be an operator satisfying

  1. Monotonicity: If f,g∈B(X)f, g \in B(X) are such that f(x)≀g(x)f(x) \leq g(x) for all x∈Xx \in X, then (Tf)(x)≀(Tg)(x)(T f)(x) \leq(T g)(x) for all x∈Xx \in X
  2. Discounting: Let the function f+af+a, for f∈B(X)f \in B(X) and a∈R+a \in \mathbf{R}_{+}be defined by (f+a)(x)=f(x)+a(f+a)(x)=f(x)+a (i.e. for all xx the number a is added to f(x))f(x)). There exists β∈(0,1)\beta \in(0,1) such that for all f∈B(X),aβ‰₯0f \in B(X), a \geq 0 and all x∈Xx \in X
    [T(f+a)](x)≀[Tf](x)+Ξ²a[T(f+a)](x) \leq[T f](x)+\beta a
    If these two conditions are satisfied, then the operator TT is a contraction with modulus Ξ²\beta.
tip

The neoclassical growth model with bounded utility satisfies the Sufficient conditions for a contraction and there is a unique fixed point to the functional equation that can be computed from any starting guess v0v_0 be repeated application of the T-operator.